| 1 |
Okay, I have corrected the loser and hp/dps typing errors.
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1 |
Okay, I have corrected the loser and hp/dps typing errors.
|
| 2 |
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2 |
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| 3 |
You can also choose other g as long as it is decreasing enough in f(Y) so that it makes the integral converge. Otherwise if Omega is infinite the integral will be infinite, too.
|
3 |
You can also choose other g as long as it is decreasing enough in f(Y) so that it makes the integral converge. Otherwise if Omega is infinite the integral will be infinite, too.
|
| 4 |
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|
4 |
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| 5 |
At
first
your
example
was
shocking
me,
but
now
I
think
that
the
integral
solves
the
problem.
Even
if
X
is
half
as
strong
as
Y,
the
integral
will
only
consider
the
battle
between
X
and
Y
as
part
of
an
average.
If
Omega
is
finite
or
even
only
Omega={
X,
Y}
,
g=1
can
be
used
to
solve
the
problem,
though.
Even
with
finite
Omega,
the
unit
group
space
(
natural
numbers)
^Omeage
is
still
infinite
and
may
require
other
weighting
functions
then.
.
.
|
5 |
At
first
your
example
was
shocking
me,
but
now
I
think
that
the
integral
solves
the
problem.
Even
if
X
is
half
as
strong
as
Y,
the
integral
will
only
consider
the
battle
between
X
and
Y
as
part
of
an
average.
If
Omega
is
finite
or
even
only
Omega={
X,
Y}
,
g=1
can
be
used
to
solve
the
problem,
though.
Even
with
finite
Omega,
the
unit
group
space
(
natural
numbers)
^Omega
is
still
infinite
and
may
require
other
weighting
functions
then.
.
.
|
| 6 |
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|
6 |
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|
| 7 |
For the hp*dps solution it would indeed be correct to integrate over dps and hp with two integrals. It can be seen that relhp's dependency in (dps_X,hp_X,dps_Y,hp_Y,t) can be reduced to {{{ (dps_X*hp_X,dps_Y*hp_Y,t). }}} I just didn't write down every step of the calculation. In fact I calculated the integral in dependency of hp*dps already. But I have just recalculated it with two integrals and get the same result.
|
7 |
For the hp*dps solution it would indeed be correct to integrate over dps and hp with two integrals. It can be seen that relhp's dependency in (dps_X,hp_X,dps_Y,hp_Y,t) can be reduced to {{{ (dps_X*hp_X,dps_Y*hp_Y,t). }}} I just didn't write down every step of the calculation. In fact I calculated the integral in dependency of hp*dps already. But I have just recalculated it with two integrals and get the same result.
|
| 8 |
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|
8 |
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|
| 9 |
[quote]I totally missed the multiset meaning of ψ, despite it being very obvious. Oops![/quote]Indeed very obvious as most forum readers will confirm :D ;)
|
9 |
[quote]I totally missed the multiset meaning of ψ, despite it being very obvious. Oops![/quote]Indeed very obvious as most forum readers will confirm :D ;)
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How to balance (calculate strength of) units in any strategy game